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0=x^2-x-120
We move all terms to the left:
0-(x^2-x-120)=0
We add all the numbers together, and all the variables
-(x^2-x-120)=0
We get rid of parentheses
-x^2+x+120=0
We add all the numbers together, and all the variables
-1x^2+x+120=0
a = -1; b = 1; c = +120;
Δ = b2-4ac
Δ = 12-4·(-1)·120
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{481}}{2*-1}=\frac{-1-\sqrt{481}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{481}}{2*-1}=\frac{-1+\sqrt{481}}{-2} $
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